Find the maximum area inside the barrier using the information from the word problem, please? - movable fencing
To the crowd at the world track and control meeting in Edmonton, will be broadly the mobile display sections 2 m and 1 m high. If 200 profiles are available, calculate the maximum rectangular area coukd closed.
The maximum area inside the barrier is ___ ^ m 2
Thank you very much.
1 comment:
Perimeter = 400
Let X, Y, are parties
2x + 2y = 400
Area = xy = x (200-x)
D (surface) / dx = 0 follows x = 100
Parts are 100 and 100 = 10,000 m ^ 2
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